/**
*死锁例子：鱼和熊不可兼得
*解决死锁的方法：同步代码块中不要相互嵌套，即，不要相互嵌套锁。
?*/
public class MyDead2 {
????public static void main(String[] args) throws InterruptedException {
Person2 personA = new Person2(0, "猎人A");
Person2 personB = new Person2(1, "猎人B");
????????personA.start();
????????personB.start();
????}
}
//熊掌
class Bear2 {
}
//鱼
class Fish2 {
}
//人
class Person2 extends Thread {
//保证资源只有一份
????public static Bear2 bear = new Bear2();
????public static Fish2 fish = new Fish2();
????int choose;
????String personName;
????public Person2 (int choose, String personName) {
????????this.choose = choose;
????????this.personName = personName;
????}
????@Override
????public void run() {
//捕猎
????????try {
????????????this.hunting();
????????} catch (InterruptedException e) {
????????????e.printStackTrace();
????????}
????}
//捕猎方法
????private void hunting() throws InterruptedException {
????????if (choose == 0) {
????????????synchronized (bear) {
System.out.println(personName + "想捕捉熊");
????????????????Thread.sleep(1000);
????????????}
//把嵌套的代码块拿到外面，两个代码块并列
????????????synchronized (fish) {
System.out.println(personName + "想捕捉鱼");
????????????}
????????} else {
????????????synchronized (fish) {
System.out.println(personName + "想捕捉鱼");
????????????????Thread.sleep(1000);
????????????}
//把嵌套的代码块拿到外面，两个代码块并列
????????????synchronized (bear) {
System.out.println(personName + "想捕捉熊");
????????????}
????????}
????}
}